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CGP EDU Academic Team
Published on: September 11, 2026
The distance between the nearest node and antinode in a stationary wave is
$(a) \lambda \quad (b) \frac{\lambda}{2} \quad (c) \frac{\lambda}{4} \quad (d) 2\lambda$
Text Solution
Verified by ExpertsThe correct answer is:
C
The distance between the nearest node and antinode in a stationary wave is $\frac{\lambda}{4}$
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